4 = 100 binary. If Poser booleans are 3-bit integers, it would make a microscopic amout of (but still some) sense to use 4 as TRUE and 0 FALSE, if it's big-endian, because it would stop reading after the initial bit and know true. The reason it's microscopic is because not even the processor itself could detect the speed difference, aspecially as the character string '4' has to be translated anyway. The reason it's kinda silly is because it would make more sense to just use a proper 1-bit bool. And because 3-bit integers are just plain silly. And because I don't think that Intel processors are big-endian anyway.