Quote - for a parabola the end point positions on Y dont matter.
the curve if from xa to xb using the solution for the equation ax^2 + bx + c
you need to solve three equations but I posted the code for that , or I can give you a python program that solves for 3 points. The hard part is getting the third point .

I think I've followed what you posted, but you've also said there are additional steps for finding the a,b, and c portions.  I'm not sure what those are meant to represent, so I'm not even sure how to begin thinking about finding them.  :lol:  I have a difficulty with new math, whereby I can't really grasp it until I can visualize it.  If I'm not able to think about it visually, or I do so using the wrong mental picture, I get rather confused.  Assuming I even get close enough to understanding to be confused.  :lol:  I suppose it isn't just math, for that matter, but any new idea.  Hmm.

I certainly won't say no, if you'd like to put up some code to get the chain posing script up and running, so we can all use it.  :laugh:  :thumbupboth:

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Cage can be an opinionated jerk who posts without thinking.  He apologizes for this.  He's honestly not trying to be a turkeyhead.

Cage had some freebies, compatible with Poser 11 and below.  His Python scripts were saved at archive.org, along with the rest of the Morphography site, where they were hosted.