Ragtopjohnny opened this issue on Jun 14, 2012 · 157 posts
gate posted Wed, 20 June 2012 at 12:28 PM
Now Look at this were already at theft... but actually the creator of this tread asked how or if it is possible to use images from the Internet !!! not stealing them .
but as soon as something might be used from another Image well then it is stolen.
you guys steal great Ideas all the even if you recreate a Jeans for the doll it was not your Invention you just stole anothers Idea.
And well Sparky you must be verry well informed about those Vip Sharing sites hoping you dont fequent em to with the excuse I'm a Undercover Agent as you would be pretty temptated to be one of those sticking arround there .
So I wonder what all this has to do with the question of Ragtopjohnny he only well the way I understand take a picture comperable with scan and use a fragment of this onto a shirt for models , now what is Ilegal about that .
If it concerns an older user Creator well then it is another discussion I remember all these Treads about WM V4 and all these sencere creatores dicussions how to avoid on the limmit of legality and change V4 and now I'm sure you also are in Posession of a copy in your runtime.
Ragtopjohnny would not be a thief as long as he does not pretend that he has been the originall creator of the cutout and gives credit.
Else we could start pretending that each collage made worldwide is an Illegal Handling against Copyright.
@ Ragtopjohnny actually it was or is the wrong place to ask sutch a question as for most people in here have lost any commen sence of reality. since the virtuality already has materialized in there world.
@ mrsparky if you take a picture of a tatoo on an arm, who is the originall owner of that digital Item ... the one who made the Picture or the one who has the actuall tatoo ???
Photographs must actually be pretty Illegal as they are just a copy of the originall and redestributed over the whole net. just another change of format ... but strange it belongs to the one who made this Photograph.