Quote - Correction:

"It's simple logic that a mesh with twice as many vertices allows twice as many different morphs than a fgure with only half as many vertices."

Never was good at statistics, but if I remember correctly I think it should be

2² = 2 x 2 = 4 times as many different morphs.

Or shouldn't it be even : Number of polygons x number of polygons = number of morphs ?

Then a high res morph would allow A GAZILLION more morphs.

:-)

Does someone know the correct formula for the theoretical number of morphs between let's say a 20.000 poly mesh and a 40.000 poly mesh ?

You might be surprised to learn that theoretically there are exactly the same number of different morphs for 20K and 40K meshes. Basically because there are the same number of vectors of numbers as there are numbers. But this is really only theoretically, in a slightly more practical world the representation of the morphs (ie how many digits are in a pz2 file) is more relevant than everything else. Then the number of morphs would square, because you could combine every possible morph in the left 20k half of the 40k polys, with every morph in the right half, which is a lot more. But the 40k morphs would be twice as big as the 20k morphs, because on the average they cover twice as many vertices, so on any given computer with fixed amount of memory you could use only half the number of morphs, so the usable number is less for 40k than for 20k; for instance, if you have only 40KB of RAM you can decide if you fill it with exactly one 40K morph, or two different 20K morphs. Of course this only is theoretical practice. In practical practice you simply have the same number of morphs for 20K and 40K (but the 40K versions are still bigger).