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Subject: I desperately need help on this.


Rayraz ( ) posted Sun, 27 October 2002 at 8:36 AM · edited Thu, 09 January 2025 at 10:01 PM

Okay, it's not a bryce question and I also posted this on the fractal forum but I thought that if I posted it here too. I might have a bigger change at a usable answer. It's a highly unusual question, but here it goes: I've got the complex values 'Z' and '#pixel' in my standard mandelbrot formula. each complex value is given by (a + bi). I've calculated that for '(a + bi)*(c + di)=(a + 2bi)' c = a^2 + b^2 and d = (ab)/(a^2 + b^2). But how do I tell ultrafractal to create the values c and d from the complex values 'Z' or from '#pixel'? I cant just tell ultrafractal: c = a^2 + b^2 d = (ab)/(a^2 + b^2) I have to define the values 'a' and 'b' too. how do I devide 'Z' and '#pixel' in the components 'a' and 'bi'? P.S:(i = sqrt(-1))

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Rayraz ( ) posted Sun, 27 October 2002 at 8:38 AM

I hope this makes sence. I have to use this to 'stretch' a mandelbrot fractal along the real or imag axis. I can't just render my fractal and stretch it in Photoshop or PSP or any other image program. It's my assignment for Math at school to do this mathematically.

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airflamesred ( ) posted Sun, 27 October 2002 at 9:18 AM

pass


tuttle ( ) posted Sun, 27 October 2002 at 10:12 AM

? Not sure what you're trying to do. Looks like you've got 2 equations and 4 unknowns, so you can never define any of the unknowns in terms of anything but other unknowns. Is there something missing?


Rayraz ( ) posted Sun, 27 October 2002 at 1:06 PM

The formula defines the #pixel variable through the codinates on the image. The pixel on the horizontal axis is a the pixel on the vertical axis is b. c and d can be written in equations with a and b, wich are known values. but the problem is that ultrafractal knows these values, but I don't know how to adress them. How does ultrafractal call these values in it's formula scripting language? What I'm trying to acheive is that I can say to Ultrafractal: Take the real component of complex value 'Z' and/or '#pixel' and call it 'a'. Take the imaginary component (imag component) of 'Z' and/or '#pixel' and call it 'b'.

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Hubert ( ) posted Sun, 27 October 2002 at 1:55 PM

Hi, sorry, I dont use UF to check its command list. Yet, arent there basic commands/functions like "real()" and "imag()" to achieve this? See e.g. at: http://www.fractalus.com/kerry/articles/uf-drawing/uf-drawing.html Hubert

"All that we see or fear, is but a Sphere inside a Sphere."     (E. A. Pryce -- Tuesday afternoon, 1845)


Rayraz ( ) posted Sun, 27 October 2002 at 2:56 PM

yes, these basic functions are available in UF, but If I say to ultrafractal to use real(z) or imag(z) it tells me to define z wich I've already done. putting a '#' in front of the 'z' also doesn't help. Basically I want to multiply my mandelbrot fractal along the imag and real axis. simply multiplying the formula with 2 makes cardionid half the normal size, but if I want to multiply it with 3 along the real axis and with 0.5 along the imag axis I have to multiply the formula with a complex value (c + di). The problem is that for each value of #pixel I need another 'c' and 'd'. Thanx for the link I'll check it out.

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EricofSD ( ) posted Sun, 27 October 2002 at 8:17 PM

Post this on the MW forum. That's a fractal program from terrain to textures and Doc Mo visits there from time to time. Legume and Calyxa can help with that too I think.


Rayraz ( ) posted Mon, 28 October 2002 at 12:06 AM

thanx

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Vile ( ) posted Mon, 28 October 2002 at 2:52 AM

The answer is always 42.


cshaftoe ( ) posted Mon, 28 October 2002 at 7:35 PM

Vile: Wrong!!!


EricofSD ( ) posted Mon, 28 October 2002 at 9:14 PM

But what's the question, vile? Is it 7 x 9 or should we search the universe to find the question to the answer? I know, ask the mice.


cshaftoe ( ) posted Tue, 29 October 2002 at 4:42 AM

I think it's a case of 'so long and thanks for all the fish' The Bryster


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